Ok, if I have a capacitor in which I know the capacitance, and then I insert a dielectric with a capacitance constant deal of 3. However, the dielectric only takes up 1/3 of the space between the plates. Does it have any effect on the capacitance? Like, does the 1/3 and the 3 just cancel out to give the original capacitance? Or, do you just times 3 by the original capacitance to get the new capacitance?